• Inverse rule ⪢⪢
Suppose that f:A￫B is a bisection where A and B are intervals.
If f is continuous on A, then f˂ is continuous on B.
┆
A function f:A￫B where A and B are intervals is a bijection if, for every b ∈ B, there exists a unique a ∈ A with f(a) = b.
http://qindex.info/i.php?x=9535
○○○ 5.2.7 Inverse rule ⪢⪢
Suppose that f:A￫B is a bisection where A and B are intervals.
If f is continuous on A, then f˂ is continuous on B.
┆
A function f:A￫B where A and B are intervals is a bijection if, for every b ∈ B, there exists a unique a ∈ A with f(a) = b.
http://qindex.info/i.php?x=5163
