• 08 Chain Rule proof
Definition of differentiation f(g(x))▽x = ｢(f(g(x+h))−f(g(x)))/h :h⨠0｣ = ｢(f(g(x+h))−f(g(x)))/(g(x+h)−g(x))·(g(x+h)−g(x))/h :h⨠0｣ = ｢(f(g(x+h))−f(g(x)))/(g(x+h)−g(x)) :h⨠0｣·｢(g(x+h)−g(x))/h :h⨠0｣ ᐥ Let g(x+h)−g(x) = t, then ｢t :h⨠0｣ = 0 and g(x+h) = g(x) ...
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